added sql file tests and code to extract the version number as a list

DBpython.py

@@ -12,6 +12,8 @@ db_host = sys.argv[2]
 db_name = sys.argv[3]
 db_password = sys.argv[4]
 
+import os
+import re
 import mysql.connector
 from mysql.connector import errorcode
 
@@ -26,6 +28,17 @@ try:
   data = cursor.fetchone()
   print("Current Database version : %s " % data)
 
+#could do a nested for loop hear the  regex.findall(f) is of type list
+  for root, dirs, files in os.walk("SQL_script_directory"):
+      for f in files:
+          if f.endswith(".sql"):
+               regex = re.compile(r'\d+')
+               test=regex.findall(f)
+               print(regex.findall(f))
+               print(type(test))
+#              print(os.path.join(root, f))
+
+
 except mysql.connector.Error as err:
   if err.errno == errorcode.ER_ACCESS_DENIED_ERROR:
     print("Something is wrong with your user name or password")